网站高端建设搜索引擎营销有哪些方式

移动零

初版(bug)

func moveZeroes(nums []int)  {if len(nums) == 1{return}// 设置两个指针fp1,fp2分别指向第一个元素和第二个元素，// 两种情况// 假如指针fp1指向元素为零// 1) *fp2!=0，则交换。// 2) *fp2=0，则fp2后移,直至*fp2!=0,与fp1交换// 假如指针fp1指向元素为不为零：// 1) *fp2=0,则fp1与fp2后移，变成第一种情况；// 2) *fp2!=0,fp1与fp2后移...temp := 0fp1, fp2 := 0, 1for _, _ = range nums{if fp2 == len(nums){break}if nums[fp1] == 0{if nums[fp2] != 0{temp = nums[fp1]nums[fp1] = nums[fp2]nums[fp2] = tempfp1++fp2++continue}else{fp2++temp = nums[fp1]nums[fp1] = nums[fp2]nums[fp2] = tempfp1++continue}  }else{fp1++fp2++continue}}
}    

可读性

func moveZeroes(nums []int) {if len(nums) == 1 {return}fp1, fp2 := 0, 1for fp2 < len(nums) {if nums[fp1] != 0 {fp1++fp2++continue}if nums[fp2] != 0 {nums[fp1], nums[fp2] = nums[fp2], nums[fp1]fp1++}fp2++}
}