龙岗网站设计讯息搜索关键词排行榜

案例介绍：

编写一个超市购物程序，在一家超市有牙刷、毛巾、水杯、苹果和香蕉五种商品，用户输入商品序列号进行商品购买，用户输入购买数量后计算出所需要花费的钱，一次购买结束后，需要用户输入“Y”或“N”，“Y”代表继续购买，“N”代表购物结束，此时需要计算并输出本次购物的总计花费的钱。商品价格如下表所示。

 运行结果：

 完整代码：

import java.util.Scanner;public class supermarket {public static void main(String[] args){Scanner scanner = new Scanner(System.in);double toothbrush = 8.8;//牙刷double towel = 10;//毛巾double cup = 18.8;//水杯double apple = 12.5;//苹果double banana =15.5;//香蕉System.out.println("------------黑马小商城------------");System.out.println("1.牙刷的价格为："+toothbrush+"元");System.out.println("2.毛巾的价格为："+towel+"元");System.out.println("3.水杯的价格为："+cup+"元");System.out.println("4.苹果的价格为："+apple+"元");System.out.println("5.香蕉的价格为："+banana+"元");System.out.println("--------------------------------");int item;//购买商品序列号int count;//购买商品的数量double total = 0;//购买商品总金额String good = "商品名";String goods = "商品量词";double price = 0;String choice = "Y";do{System.out.print("请输入您需要购买商品的序列号：");item = scanner.nextInt();switch (item){   //将序列号对应的商品名、商品量词、商品价格分别赋值给good、goods、pricecase 1: good = "牙刷";    goods = "把";    price = toothbrush; break;case 2: good = "毛巾";    goods = "条";    price = towel;      break;case 3: good = "水杯";    goods = "个";    price = cup;        break;case 4: good = "苹果";    goods = "斤";    price = apple;      break;case 5: good = "香蕉";    goods = "斤";    price =banana;      break;default:item=0;//若序列号输入错误，将item赋值为0System.out.println("---------商品序列号输入错误---------");}if(item!=0) //序列号输入正确，执行if语句{   System.out.print("请输入您需要购买" + good + "的数量：");count = scanner.nextInt();total = total + count * price;System.out.println("您购买了" + good + count + goods + "，需要花费" + count * price + "元");}System.out.print("需要继续购买请输入Y，否则输入N：");choice = scanner.next();while(!choice.equals("Y")&&!choice.equals("N"))//若输入字母不为Y或N，则进入while循环{System.out.println("--------是否继续购买识别失败--------");System.out.print("需要继续购买请输入Y，否则输入N：");choice = scanner.next();}//输入"Y"循环继续，输入"N"循环退出}while(choice.equals("Y"));System.out.println("您本次购物共花费 "+total+" 元");System.out.println("期待您的下次光临！");}
}