当前位置: 首页 > news >正文

excel表如何做网站连接网站推广途径和要点

excel表如何做网站连接,网站推广途径和要点,南昌百度推广联系方式,网站死链查询手写红黑树【数据结构】 前言版权推荐手写红黑树一、理论知识红黑树的特征增加删除 二、手写代码初始-树结点初始-红黑树初始-遍历初始-判断红黑树是否有效查找增加-1.父为黑,直接插入增加-2. 父叔为红,颜色调换增加-3. 父红叔黑,颜色调换&am…

手写红黑树【数据结构】

  • 前言
  • 版权
  • 推荐
  • 手写红黑树
    • 一、理论知识
      • 红黑树的特征
      • 增加
      • 删除
    • 二、手写代码
      • 初始-树结点
      • 初始-红黑树
      • 初始-遍历
      • 初始-判断红黑树是否有效
      • 查找
      • 增加-1.父为黑,直接插入
      • 增加-2. 父叔为红,颜色调换
      • 增加-3. 父红叔黑,颜色调换,再移动
      • 增加-4. 父子不同向,先掰直,再执行第3种情况
      • 测试增加
      • 删除-0 初始化数据
      • 删除-1.单个红节点 直接删除
      • 删除-3.带有一个子节点
      • 删除-4.带有两个子节点
      • 删除-2.单个黑结点
        • 2.1.1兄黑,对侄红
        • 2.1.2兄黑,顺侄红
        • 2.1.3 兄黑,双侄黑
      • 删除-2.单个黑结点 2.2兄红
      • 测试删除
  • 附录源码
  • 最后

前言

2024-3-30 10:52:57

昨天晚上B站看到的视频
00:00~01:00

以下内容源自《【数据结构】》
仅供学习交流使用

版权

禁止其他平台发布时删除以下此话
本文首次发布于CSDN平台
作者是CSDN@日星月云
博客主页是https://jsss-1.blog.csdn.net
禁止其他平台发布时删除以上此话

推荐

我红黑树那么牛,你们凭什么不用我?

手写红黑树

一、理论知识

红黑树的特征

红黑树是一种二叉平衡树,只不过这个平衡不是那么严苛,只需黑平衡就行

  1. 结点分为两种颜色
  2. 根节点是黑色
  3. 叶子结点是黑色的,叶子结点是不存储数据的空结点
  4. 两个红结点不能相连,即红父亲的孩子都是黑色的
  5. 对于任意一个结点,其到叶子结点的路径上的黑色结点数量是一致的

增加

视频

插入结点的颜色是红色的
因为是黑平衡,所以插入红结点有概率不会破坏这个规则

  1. 父为黑,直接插入
  2. 父叔为红,颜色调换
  3. 父红叔黑,颜色调换,再移动
  4. 父子不同向,先掰直,再执行第3种情况

删除

视频

https://www.processon.com/view/link/6550422f54fca5688e143664
在这里插入图片描述

二、手写代码

为了实现简单,加入parent的指针,和isLeaf的标记

可以使用HashMap用来记录每一个叶子结点的父亲结点,即键是叶子,值是父亲;
也可以直接在Node结点中加入双亲指针。
根节点的父亲结点是null
特别注意的是,parent的维护

如果是叶子结点,它的isLeaf的值为true。

初始-树结点

//结点
class TreeNode {//true是黑色,false是红色boolean color;//数据Integer data;TreeNode left;TreeNode right;private static final boolean RED = false;private static final boolean BLACK = true;//是否是叶子结点boolean isLeaf;//方便实现TreeNode parent;public TreeNode() {}public TreeNode(int data) {this.data = data;}public TreeNode(boolean color, Integer data) {this.color = color;this.data = data;}public TreeNode(boolean color, Integer data, TreeNode parent) {this.color = color;this.data = data;this.parent = parent;}public TreeNode(boolean color, Integer data, TreeNode parent, boolean isLeaf) {this.color = color;this.data = data;this.parent = parent;this.isLeaf = isLeaf;}//    public TreeNode(Integer data,TreeNode left, TreeNode right) {
//        this.data = data;
//        this.left = left;
//        this.right = right;
//    }public boolean isBlack() {return color == BLACK;}@Overridepublic String toString() {return "TreeNode{" +"color=" + color +", data=" + data +'}';}}

初始-红黑树


package test;import java.util.LinkedList;
import java.util.Queue;public class RedBlackTree {private static final boolean RED = false;private static final boolean BLACK = true;//根结点TreeNode root;public void initRoot(int data) {root = new TreeNode(BLACK, data, null, false);TreeNode nil = new TreeNode(BLACK, null, root, true);root.left = nil;root.right = nil;}/*** 增加* 1. 父为黑,直接插入* 2. 父叔为红,颜色调换* 3. 父红叔黑,颜色调换,再移动* 4. 父子不同向,先掰直,再执行第3种情况** @param data 数据*/public void add(int data) {}/***  删除* 1.单个红节点  直接删除* 2.单个黑节点*      2.1兄黑*         2.1.1 对侄红 (指方向相反的侄节点)*               父兄交替旋转、然后按父红兄弟黑换色 (最后一步的换色,父红两兄弟黑,是按交替旋转之后的关系处理。)*         2.1.2 顺侄红(指方向相同的侄节点)*              兄侄交替旋转,并调换颜色,就会变成对侄红,然后按2.1.1处理*         2.1.3 双侄黑*              兄变红父变黑,如果父本身就是黑,就以父亲角度按情况2处理**      2.2 兄红*              父兄交替旋转,并调换颜色,新的兄节点将变黑,在按2.1处理* 3.带有一个子节点(当一个节点只有一个子节点时(空叶子除外),该节点必定是黑节点,其子节点必定是红色)*      用红子节点值替换,然后直接删除红子节点* 4.带有两个子节点!*      找到左子树中最靠右的子节点,用该节点值替换,并删除该节点按情况1,2,3处理(左子树中最大的值,也是离其最近的值)** @param data 数据*/public void delete(int data) {}public static void main(String[] args) {RedBlackTree tree = new RedBlackTree();tree.inorder(tree.root);
//        tree.levelOrder(tree.root);}}

初始-遍历

 //中序遍历public void inorder(TreeNode root) {if (root == null) {return;}if (!root.left.isLeaf) {inorder(root.left);}System.out.println(root);if (!root.right.isLeaf) {inorder(root.right);}}//层序遍历public void levelOrder(TreeNode root) {if (root == null) {return;}Queue<TreeNode> queue = new LinkedList<>();queue.add(root);while (!queue.isEmpty()) {int size = queue.size();for (int i = 0; i < size; i++) {TreeNode cur = queue.poll();System.out.print(cur + "\t");if (cur.left != null) {queue.add(cur.left);}if (cur.right != null) {queue.add(cur.right);}}System.out.println();}}

初始-判断红黑树是否有效

    //判断是否是有效的红黑树public static boolean isValidRedBlackTree(TreeNode root) {if (root == null) {return true;}// 检查根节点是否是黑色if (root.color != BLACK) {return false;}// 计算黑高度,并检查红黑平衡blackHeight = -1;if (!checkBlackBalance(root, 0)) {return false;}// 递归检查每个节点return isValidRedBlackSubtree(root);}private static boolean checkBlackBalance(TreeNode node, int currentBlackHeight) {if (node.isLeaf) {if (blackHeight == -1) {blackHeight = currentBlackHeight;return true;} else {return currentBlackHeight == blackHeight;}}if (node.color == BLACK) {currentBlackHeight++;}return checkBlackBalance(node.left, currentBlackHeight) && checkBlackBalance(node.right, currentBlackHeight);}private static boolean isValidRedBlackSubtree(TreeNode node) {if (node == null) {return true;}// 检查红黑树性质if (node.color == RED) {if ((node.left != null && node.left.color != BLACK) || (node.right != null && node.right.color != BLACK)) {return false;}}// 递归检查左右子树return isValidRedBlackSubtree(node.left) && isValidRedBlackSubtree(node.right);}

查找

 	/*** 查找** @param data 数据* @return 查找结点,如果差不到就会返回叶子结点*/public TreeNode find(int data) {TreeNode find = root;while (!find.isLeaf) {if (data < find.data) {find = find.left;} else if(data==find.data){return find;} else if (data > find.data) {find = find.right;}}return find;}

增加-1.父为黑,直接插入

   /*** 增加* 1. 父为黑,直接插入* 2. 父叔为红,颜色调换* 3. 父红叔黑,颜色调换,再移动* 4. 父子不同向,先掰直,再执行第3种情况** @param data 数据*/public void add(int data) {if (root == null) {initRoot(data);return;}TreeNode find = find(data);if (!find.isLeaf) {System.out.println("不能插入相同数据的结点");return;}TreeNode parent = find.parent;TreeNode newNode = new TreeNode(RED, data, parent);TreeNode nil = new TreeNode(BLACK, null, newNode, true);newNode.left = nil;newNode.right = nil;if (data < parent.data) {parent.left = newNode;} else {parent.right = newNode;}//1.父为黑,直接插入if (parent.isBlack()) {//不需要额外的操作} else {//跳转2...}

增加-2. 父叔为红,颜色调换

    TreeNode grandpa = parent.parent;TreeNode uncle = grandpa.left != parent ? grandpa.left : grandpa.right;//2. 父叔为红,颜色调换if (!uncle.isBlack()) {parent.color = BLACK;uncle.color = BLACK;grandpa.color = RED;//如果爷爷是根节点if (grandpa == root) {grandpa.color = BLACK;return;}//爷爷变成红色后,它的父叔可能为红TreeNode cur=grandpa;parent=cur.parent;grandpa=parent.parent;if (parent==null||grandpa==null){return;}uncle=grandpa.left != parent ? grandpa.left : grandpa.right;while (!cur.isBlack()&&!parent.isBlack()&&!uncle.isBlack()){parent.color = BLACK;uncle.color = BLACK;grandpa.color = RED;//如果爷爷是根节点if (grandpa == root) {grandpa.color = BLACK;break;}cur=grandpa;parent=cur.parent;grandpa=parent.parent;uncle=grandpa.left != parent ? grandpa.left : grandpa.right;}} else {//跳转3...}

增加-3. 父红叔黑,颜色调换,再移动

//跳转3...boolean right1 = data > parent.data;boolean right2 = parent.data > grandpa.data;boolean direct1 = right1 && right2;boolean left1 = data < parent.data;boolean left2 = parent.data < grandpa.data;boolean direct2 = left1 && left2;//3. 父红叔黑,颜色调换,再移动if (direct1 || direct2) {op(data, parent, grandpa);} else {//跳转4...}public void op(int data, TreeNode parent, TreeNode grandpa) {boolean right1 = data > parent.data;boolean right2 = parent.data > grandpa.data;boolean direct1 = right1 && right2;boolean left1 = data < parent.data;boolean left2 = parent.data < grandpa.data;boolean direct2 = left1 && left2;boolean tmp = grandpa.color;grandpa.color = parent.color;parent.color = tmp;TreeNode grandpaPa = grandpa.parent;if (parent.data < grandpaPa.data) {grandpaPa.left = parent;} else {grandpaPa.right = parent;}parent.parent = grandpaPa;if (direct1) {parent.left = grandpa;grandpa.parent = parent;} else if (direct2) {parent.right = grandpa;grandpa.parent = parent;}grandpa.left = new TreeNode(BLACK, null, grandpa, true);grandpa.right = new TreeNode(BLACK, null, grandpa, true);}

增加-4. 父子不同向,先掰直,再执行第3种情况

					//跳转4...//4. 父子不同向,先掰直,再执行第3种情况if (left1) {grandpa.right = newNode;newNode.right = parent;}if (right1) {grandpa.left = newNode;newNode.left = parent;}newNode.parent = grandpa;parent.parent = newNode;TreeNode newNil = new TreeNode(BLACK, null, parent, true);parent.left = newNil;parent.right = newNil;op(parent.data, newNode, grandpa);

测试增加

    public static void main(String[] args) {RedBlackTree tree = new RedBlackTree();testAdd(tree);}private static void testAdd(RedBlackTree tree) {tree.add(157);//0tree.add(12);//1tree.add(200);//1tree.add(250);//2tree.add(260);//3tree.add(220);//2tree.add(210);//4tree.add(11);//1tree.add(10);//3tree.add(7);//2tree.add(9);//4tree.inorder(tree.root);
//        tree.levelOrder(tree.root);System.out.println(isValidRedBlackTree(tree.root));}

11、10、7、9的插入图如下
在这里插入图片描述

在这里插入图片描述

在这里插入图片描述

2024-3-30 15:35:56

删除-0 初始化数据

在这里插入图片描述

    public static void main(String[] args) {RedBlackTree tree = new RedBlackTree();
//        testAdd(tree);initData(tree);}private static void initData(RedBlackTree tree) {int[] nums={430,261,636,95,344,559,822,37,131,330,369,499,594,705,981,262,345,485,664,818};for (int i = 0; i < nums.length; i++) {tree.add(nums[i]);}//        tree.inorder(tree.root);tree.levelOrder(tree.root);System.out.println(isValidRedBlackTree(tree.root));}

删除-1.单个红节点 直接删除

 /***  删除* 1.单个红节点  直接删除* 2.单个黑节点*      2.1兄黑*         2.1.1 对侄红 (指方向相反的侄节点)*               父兄交替旋转、然后按父红兄弟黑换色 (最后一步的换色,父红两兄弟黑,是按交替旋转之后的关系处理。)*         2.1.2 顺侄红(指方向相同的侄节点)*              兄侄交替旋转,并调换颜色,就会变成对侄红,然后按2.1.1处理*         2.1.3 双侄黑*              兄变红父变黑,如果父本身就是黑,就以父亲角度按情况2处理**      2.2 兄红*              父兄交替旋转,并调换颜色,新的兄节点将变黑,在按2.1处理* 3.带有一个子节点(当一个节点只有一个子节点时(空叶子除外),该节点必定是黑节点,其子节点必定是红色)*      用红子节点值替换,然后直接删除红子节点* 4.带有两个子节点*      找到左子树中最靠右的子节点,用该节点值替换,并删除该节点按情况1,2,3处理(左子树中最大的值,也是离其最近的值)** @param data 数据*/public void delete(int data) {TreeNode find = find(data);if (find.isLeaf){System.out.println("没有找到");return;}//1.单个红节点if (!find.isBlack()){if (find.left.isLeaf&&find.right.isLeaf){TreeNode parent = find.parent;TreeNode nil=new TreeNode(BLACK,null,parent,true);if (data<parent.data){parent.left=nil;}else {parent.right=nil;}}else {//4.带有两个子节点}}else {//3.带有一个子节点,用红子节点值替换,然后直接删除红子节点}}

删除-3.带有一个子节点

			//3.带有一个子节点,用红子节点值替换,然后直接删除红子节点if (find.left.isLeaf&&!find.right.isBlack()){find.data=find.right.data;find.right= new TreeNode(BLACK,null,find,true);}else if (find.right.isLeaf&&!find.left.isBlack()){find.data=find.left.data;find.left= new TreeNode(BLACK,null,find,true);} 

删除-4.带有两个子节点

			else if (!find.left.isLeaf&&!find.right.isLeaf){//4.带有两个子节点TreeNode replace = findReplace(find);delete(replace.data);find.data= replace.data;}else {//2.单个黑结点/*** 查找替代的结点* 中序遍历线索树的直接前驱结点* @param node 删除的结点* @return 查找替代*/public TreeNode findReplace(TreeNode node) {TreeNode left = node.left;while (!left.isLeaf) {left=left.right;}return left.parent;}

删除-2.单个黑结点

2.1.1兄黑,对侄红
  				TreeNode parent=find.parent;TreeNode brother=parent.left!=find?parent.left:parent.right;boolean left=find.data<parent.data;//对侄TreeNode duiNephew=left?brother.right:brother.left;//顺侄TreeNode shunNephew=left?brother.left:brother.right;if (brother.isBlack()){//2.1兄黑//2.1.1 对侄红TreeNode duiNephew=left?brother.right:brother.left;if (!duiNephew.isBlack()){//父兄交替旋转TreeNode grandpa=parent.parent;if (brother.data<grandpa.data){grandpa.left=brother;}else {grandpa.right=brother;}brother.parent=grandpa;if (left){brother.left=parent;}else {brother.right=parent;}parent.parent=brother;TreeNode nil=new TreeNode(BLACK,null,parent,true);parent.left=nil;parent.right=nil;//并调换颜色brother.color=RED;duiNephew.color=BLACK;parent.color=BLACK;}else if (!shunNephew.isBlack()){//2.1.2 顺侄红}else if (brother.left.isBlack()&&brother.right.isBlack()){//2.1.3 双侄黑}else{//兄红}
2.1.2兄黑,顺侄红
                        //兄侄交替旋转,并调换颜色,就会变成对侄红,if (brother.data< parent.data){parent.left=shunNephew;shunNephew.left=brother;}else {parent.right=shunNephew;shunNephew.right=brother;}shunNephew.parent=parent;brother.parent=shunNephew;TreeNode nil=new TreeNode(BLACK,null,brother,true);brother.left=nil;brother.right=nil;brother.color=RED;shunNephew.color=BLACK;delete(data);
2.1.3 兄黑,双侄黑
                        //兄变红父变黑,如果父本身就是黑,就以父亲角度按情况2处理brother.color=RED;parent.color=BLACK;TreeNode nil=new TreeNode(BLACK,null,parent,true);if (find.data< parent.data){parent.left=nil;}else {parent.right=nil;}

删除-2.单个黑结点 2.2兄红

					//父兄交替旋转,并调换颜色,新的兄节点将变黑,在按2.1处理TreeNode grandpa=parent.parent;if (brother.data<grandpa.data){grandpa.left=brother;}else {grandpa.right=brother;}brother.parent=grandpa;TreeNode tmp;if (data<parent.data){tmp=brother.left;brother.left=parent;}else {tmp=brother.right;brother.right=parent;}parent.parent=brother;if (data<parent.data){parent.left=find;parent.right=tmp;}else {parent.left=tmp;parent.right=find;}brother.color=BLACK;parent.color=RED;delete(data);

测试删除

    public static void main(String[] args) {RedBlackTree tree = new RedBlackTree();
//        testAdd(tree);initData(tree);testDelete(tree);tree.levelOrder(tree.root);System.out.println(isValidRedBlackTree(tree.root));}private static void testDelete(RedBlackTree tree) {tree.delete(262);//1tree.delete(818);//1tree.delete(705);//3tree.delete(369);//3tree.add(346);tree.delete(430);//4tree.delete(594);//2.1.1tree.add(570);tree.delete(485);//2.1.1tree.add(565);tree.delete(499);//2.1.2tree.add(335);tree.delete(345);//2.1.2tree.delete(559);//2.1.3tree.delete(570);tree.delete(565);//2.2tree.delete(37);tree.delete(131);tree.delete(95);//2.2}

在这里插入图片描述

附录源码

package test;import java.util.LinkedList;
import java.util.Queue;public class RedBlackTree {private static final boolean RED = false;private static final boolean BLACK = true;//根结点TreeNode root;public void initRoot(int data) {root = new TreeNode(BLACK, data, null, false);TreeNode nil = new TreeNode(BLACK, null, root, true);root.left = nil;root.right = nil;}/*** 增加* 1. 父为黑,直接插入* 2. 父叔为红,颜色调换* 3. 父红叔黑,颜色调换,再移动* 4. 父子不同向,先掰直,再执行第3种情况** @param data 数据*/public void add(int data) {if (root == null) {initRoot(data);return;}TreeNode find = find(data);if (!find.isLeaf) {System.out.println("不能插入相同数据的结点");return;}TreeNode parent = find.parent;TreeNode newNode = new TreeNode(RED, data, parent);TreeNode nil = new TreeNode(BLACK, null, newNode, true);newNode.left = nil;newNode.right = nil;if (data < parent.data) {parent.left = newNode;} else {parent.right = newNode;}//1.父为黑,直接插入if (parent.isBlack()) {//不需要额外的操作} else {TreeNode grandpa = parent.parent;TreeNode uncle = grandpa.left != parent ? grandpa.left : grandpa.right;//2. 父叔为红,颜色调换if (!uncle.isBlack()) {parent.color = BLACK;uncle.color = BLACK;grandpa.color = RED;//如果爷爷是根节点if (grandpa == root) {grandpa.color = BLACK;return;}//爷爷变成红色后,它的父叔可能为红TreeNode cur=grandpa;parent=cur.parent;grandpa=parent.parent;if (parent==null||grandpa==null){return;}uncle=grandpa.left != parent ? grandpa.left : grandpa.right;while (!cur.isBlack()&&!parent.isBlack()&&!uncle.isBlack()){parent.color = BLACK;uncle.color = BLACK;grandpa.color = RED;//如果爷爷是根节点if (grandpa == root) {grandpa.color = BLACK;break;}cur=grandpa;parent=cur.parent;grandpa=parent.parent;uncle=grandpa.left != parent ? grandpa.left : grandpa.right;}} else {boolean right1 = data > parent.data;boolean right2 = parent.data > grandpa.data;boolean direct1 = right1 && right2;boolean left1 = data < parent.data;boolean left2 = parent.data < grandpa.data;boolean direct2 = left1 && left2;//3. 父红叔黑,颜色调换,再移动if (direct1 || direct2) {op(data, parent, grandpa);} else {//4. 父子不同向,先掰直,再执行第3种情况if (left1) {grandpa.right = newNode;newNode.right = parent;}if (right1) {grandpa.left = newNode;newNode.left = parent;}newNode.parent = grandpa;parent.parent = newNode;TreeNode newNil = new TreeNode(BLACK, null, parent, true);parent.left = newNil;parent.right = newNil;op(parent.data, newNode, grandpa);}}}}public void op(int data, TreeNode parent, TreeNode grandpa) {boolean right1 = data > parent.data;boolean right2 = parent.data > grandpa.data;boolean direct1 = right1 && right2;boolean left1 = data < parent.data;boolean left2 = parent.data < grandpa.data;boolean direct2 = left1 && left2;boolean tmp = grandpa.color;grandpa.color = parent.color;parent.color = tmp;TreeNode grandpaPa = grandpa.parent;if (parent.data < grandpaPa.data) {grandpaPa.left = parent;} else {grandpaPa.right = parent;}parent.parent = grandpaPa;if (direct1) {parent.left = grandpa;grandpa.parent = parent;} else if (direct2) {parent.right = grandpa;grandpa.parent = parent;}grandpa.left = new TreeNode(BLACK, null, grandpa, true);grandpa.right = new TreeNode(BLACK, null, grandpa, true);}/***  删除* 1.单个红节点  直接删除* 2.单个黑节点*      2.1兄黑*         2.1.1 对侄红 (指方向相反的侄节点)*               父兄交替旋转、然后按父红兄弟黑换色 (最后一步的换色,父红两兄弟黑,是按交替旋转之后的关系处理。)*         2.1.2 顺侄红(指方向相同的侄节点)*              兄侄交替旋转,并调换颜色,就会变成对侄红,然后按2.1.1处理*         2.1.3 双侄黑*              兄变红父变黑,如果父本身就是黑,就以父亲角度按情况2处理**      2.2 兄红*              父兄交替旋转,并调换颜色,新的兄节点将变黑,在按2.1处理* 3.带有一个子节点(当一个节点只有一个子节点时(空叶子除外),该节点必定是黑节点,其子节点必定是红色)*      用红子节点值替换,然后直接删除红子节点* 4.带有两个子节点*      找到左子树中最靠右的子节点,用该节点值替换,并删除该节点按情况1,2,3处理(左子树中最大的值,也是离其最近的值)** @param data 数据*/public void delete(int data) {TreeNode find = find(data);if (find.isLeaf){System.out.println("没有找到");return;}//1.单个红节点if (!find.isBlack()){if (find.left.isLeaf&&find.right.isLeaf){TreeNode parent = find.parent;TreeNode nil=new TreeNode(BLACK,null,parent,true);if (data<parent.data){parent.left=nil;}else {parent.right=nil;}}else {//4.带有两个子节点TreeNode replace = findReplace(find);delete(replace.data);find.data= replace.data;}}else {//3.带有一个子节点,用红子节点值替换,然后直接删除红子节点if (find.left.isLeaf&&!find.right.isBlack()){find.data=find.right.data;find.right= new TreeNode(BLACK,null,find,true);}else if (find.right.isLeaf&&!find.left.isBlack()){find.data=find.left.data;find.left= new TreeNode(BLACK,null,find,true);} else if (!find.left.isLeaf&&!find.right.isLeaf){//4.带有两个子节点TreeNode replace = findReplace(find);delete(replace.data);find.data= replace.data;}else {//2.单个黑结点TreeNode parent=find.parent;TreeNode brother=parent.left!=find?parent.left:parent.right;boolean left=find.data<parent.data;//对侄TreeNode duiNephew=left?brother.right:brother.left;//顺侄TreeNode shunNephew=left?brother.left:brother.right;if (brother.isBlack()){//2.1兄黑//2.1.1 对侄红if (!duiNephew.isBlack()){//父兄交替旋转TreeNode grandpa=parent.parent;if (brother.data<grandpa.data){grandpa.left=brother;}else {grandpa.right=brother;}brother.parent=grandpa;if (left){brother.left=parent;}else {brother.right=parent;}parent.parent=brother;TreeNode nil=new TreeNode(BLACK,null,parent,true);parent.left=nil;parent.right=nil;//并调换颜色brother.color=RED;duiNephew.color=BLACK;parent.color=BLACK;} else if (!shunNephew.isBlack()){//2.1.2 顺侄红//兄侄交替旋转,并调换颜色,就会变成对侄红,if (brother.data< parent.data){parent.left=shunNephew;shunNephew.left=brother;}else {parent.right=shunNephew;shunNephew.right=brother;}shunNephew.parent=parent;brother.parent=shunNephew;TreeNode nil=new TreeNode(BLACK,null,brother,true);brother.left=nil;brother.right=nil;brother.color=RED;shunNephew.color=BLACK;delete(data);} else if (brother.left.isBlack()&&brother.right.isBlack()){//2.1.3 双侄黑//兄变红父变黑,如果父本身就是黑,就以父亲角度按情况2处理brother.color=RED;parent.color=BLACK;TreeNode nil=new TreeNode(BLACK,null,parent,true);if (find.data< parent.data){parent.left=nil;}else {parent.right=nil;}}}else {//2.2兄红//父兄交替旋转,并调换颜色,新的兄节点将变黑,在按2.1处理TreeNode grandpa=parent.parent;if (brother.data<grandpa.data){grandpa.left=brother;}else {grandpa.right=brother;}brother.parent=grandpa;TreeNode tmp;if (data<parent.data){tmp=brother.left;brother.left=parent;}else {tmp=brother.right;brother.right=parent;}parent.parent=brother;if (data<parent.data){parent.left=find;parent.right=tmp;}else {parent.left=tmp;parent.right=find;}brother.color=BLACK;parent.color=RED;delete(data);}}}}/*** 查找** @param data 数据* @return 查找结点,如果差不到就会返回叶子结点*/public TreeNode find(int data) {TreeNode find = root;while (!find.isLeaf) {if (data < find.data) {find = find.left;} else if(find.data.equals(data)){return find;} else if (data > find.data) {find = find.right;}}return find;}/*** 查找替代的结点* 中序遍历线索树的直接前驱结点* @param node 删除的结点* @return 查找替代*/public TreeNode findReplace(TreeNode node) {TreeNode left = node.left;while (!left.isLeaf) {left=left.right;}return left.parent;}//中序遍历public void inorder(TreeNode root) {if (root == null) {return;}if (!root.left.isLeaf) {inorder(root.left);}System.out.println(root);if (!root.right.isLeaf) {inorder(root.right);}}//层序遍历public void levelOrder(TreeNode root) {if (root == null) {return;}Queue<TreeNode> queue = new LinkedList<>();queue.add(root);while (!queue.isEmpty()) {int size = queue.size();for (int i = 0; i < size; i++) {TreeNode cur = queue.poll();System.out.print(cur + "\t");if (cur.left != null) {queue.add(cur.left);}if (cur.right != null) {queue.add(cur.right);}}System.out.println();}}private static int blackHeight = -1;//判断是否是有效的红黑树public static boolean isValidRedBlackTree(TreeNode root) {if (root == null) {return true;}// 检查根节点是否是黑色if (root.color != BLACK) {return false;}// 计算黑高度,并检查红黑平衡blackHeight = -1;if (!checkBlackBalance(root, 0)) {return false;}// 递归检查每个节点return isValidRedBlackSubtree(root);}private static boolean checkBlackBalance(TreeNode node, int currentBlackHeight) {if (node.isLeaf) {if (blackHeight == -1) {blackHeight = currentBlackHeight;return true;} else {return currentBlackHeight == blackHeight;}}if (node.color == BLACK) {currentBlackHeight++;}return checkBlackBalance(node.left, currentBlackHeight) && checkBlackBalance(node.right, currentBlackHeight);}private static boolean isValidRedBlackSubtree(TreeNode node) {if (node == null) {return true;}// 检查红黑树性质if (node.color == RED) {if ((node.left != null && node.left.color != BLACK) || (node.right != null && node.right.color != BLACK)) {return false;}}// 递归检查左右子树return isValidRedBlackSubtree(node.left) && isValidRedBlackSubtree(node.right);}public static void main(String[] args) {RedBlackTree tree = new RedBlackTree();
//        testAdd(tree);initData(tree);testDelete(tree);tree.levelOrder(tree.root);System.out.println(isValidRedBlackTree(tree.root));}private static void testDelete(RedBlackTree tree) {tree.delete(262);//1tree.delete(818);//1tree.delete(705);//3tree.delete(369);//3tree.add(346);tree.delete(430);//4tree.delete(594);//2.1.1tree.add(570);tree.delete(485);//2.1.1tree.add(565);tree.delete(499);//2.1.2tree.add(335);tree.delete(345);//2.1.2tree.delete(559);//2.1.3tree.delete(570);tree.delete(565);//2.2tree.delete(37);tree.delete(131);tree.delete(95);//2.2}private static void initData(RedBlackTree tree) {int[] nums={430,261,636,95,344,559,822,37,131,330,369,499,594,705,981,262,345,485,664,818};for (int i = 0; i < nums.length; i++) {tree.add(nums[i]);}//        tree.inorder(tree.root);
//        tree.levelOrder(tree.root);
//        System.out.println(isValidRedBlackTree(tree.root));}private static void testAdd(RedBlackTree tree) {tree.add(157);//0tree.add(12);//1tree.add(200);//1tree.add(250);//2tree.add(260);//3tree.add(220);//2tree.add(210);//4tree.add(11);//1tree.add(10);//3tree.add(7);//2tree.add(9);//4tree.inorder(tree.root);
//        tree.levelOrder(tree.root);System.out.println(isValidRedBlackTree(tree.root));}}//结点
class TreeNode {//true是黑色,false是红色boolean color;//数据Integer data;TreeNode left;TreeNode right;private static final boolean RED = false;private static final boolean BLACK = true;//是否是叶子结点boolean isLeaf;//方便实现TreeNode parent;public TreeNode() {}public TreeNode(int data) {this.data = data;}public TreeNode(boolean color, Integer data) {this.color = color;this.data = data;}public TreeNode(boolean color, Integer data, TreeNode parent) {this.color = color;this.data = data;this.parent = parent;}public TreeNode(boolean color, Integer data, TreeNode parent, boolean isLeaf) {this.color = color;this.data = data;this.parent = parent;this.isLeaf = isLeaf;}//    public TreeNode(Integer data,TreeNode left, TreeNode right) {
//        this.data = data;
//        this.left = left;
//        this.right = right;
//    }public boolean isBlack() {return color == BLACK;}@Overridepublic String toString() {return "TreeNode{" +"color=" + color +", data=" + data +'}';}}

最后

2024-3-30 23:05:13

写了一天

迎着日光月光星光,直面风霜雨霜雪霜。


文章转载自:
http://colorably.nrwr.cn
http://bluebird.nrwr.cn
http://nitrosodimethylamine.nrwr.cn
http://embalm.nrwr.cn
http://silverweed.nrwr.cn
http://cursive.nrwr.cn
http://microorder.nrwr.cn
http://capitalist.nrwr.cn
http://suckling.nrwr.cn
http://knobby.nrwr.cn
http://narrowfisted.nrwr.cn
http://coprecipitation.nrwr.cn
http://fundamentality.nrwr.cn
http://courses.nrwr.cn
http://ascorbate.nrwr.cn
http://syncrisis.nrwr.cn
http://cuniculus.nrwr.cn
http://tobago.nrwr.cn
http://conchiolin.nrwr.cn
http://asquint.nrwr.cn
http://anisotropy.nrwr.cn
http://copra.nrwr.cn
http://gurnard.nrwr.cn
http://ablutionary.nrwr.cn
http://desmitis.nrwr.cn
http://medan.nrwr.cn
http://pantomorphic.nrwr.cn
http://chelonian.nrwr.cn
http://psychological.nrwr.cn
http://microtome.nrwr.cn
http://deodorization.nrwr.cn
http://anthodium.nrwr.cn
http://conceptus.nrwr.cn
http://elastoplastic.nrwr.cn
http://abjection.nrwr.cn
http://calorize.nrwr.cn
http://amorism.nrwr.cn
http://trichroic.nrwr.cn
http://survivor.nrwr.cn
http://extenuatory.nrwr.cn
http://hebraism.nrwr.cn
http://yi.nrwr.cn
http://ochrea.nrwr.cn
http://deedbox.nrwr.cn
http://officiously.nrwr.cn
http://incompetent.nrwr.cn
http://deianira.nrwr.cn
http://outwell.nrwr.cn
http://straucht.nrwr.cn
http://sampling.nrwr.cn
http://ideogram.nrwr.cn
http://chophouse.nrwr.cn
http://brickfielder.nrwr.cn
http://mandoline.nrwr.cn
http://hist.nrwr.cn
http://divaricate.nrwr.cn
http://binominal.nrwr.cn
http://shewbread.nrwr.cn
http://asportation.nrwr.cn
http://annihilator.nrwr.cn
http://cachinnate.nrwr.cn
http://comfily.nrwr.cn
http://massify.nrwr.cn
http://stockjobber.nrwr.cn
http://abiological.nrwr.cn
http://subdivisible.nrwr.cn
http://irreligious.nrwr.cn
http://curtness.nrwr.cn
http://tetrachloroethane.nrwr.cn
http://psst.nrwr.cn
http://russianise.nrwr.cn
http://kbp.nrwr.cn
http://louvered.nrwr.cn
http://poised.nrwr.cn
http://asexuality.nrwr.cn
http://unbent.nrwr.cn
http://lascar.nrwr.cn
http://triturable.nrwr.cn
http://anaphrodisiac.nrwr.cn
http://pyranometer.nrwr.cn
http://overchurched.nrwr.cn
http://acquittal.nrwr.cn
http://nonfat.nrwr.cn
http://acajou.nrwr.cn
http://propulsory.nrwr.cn
http://evolutionism.nrwr.cn
http://lipping.nrwr.cn
http://brewage.nrwr.cn
http://tranquillization.nrwr.cn
http://progressivism.nrwr.cn
http://pki.nrwr.cn
http://brome.nrwr.cn
http://zinckenite.nrwr.cn
http://solidus.nrwr.cn
http://gemmy.nrwr.cn
http://chemonuclear.nrwr.cn
http://allopath.nrwr.cn
http://licence.nrwr.cn
http://croze.nrwr.cn
http://minna.nrwr.cn
http://www.dt0577.cn/news/93113.html

相关文章:

  • 网站开发与推广方向长春网站建设解决方案
  • 把自己的网站卖给别人后对方做违法湖北疫情最新消息
  • flash网站代码下载百度一下你就知道移动首页
  • 网站可以只做移动端吗网络广告营销经典案例
  • 做关键字要改网站代发广告平台
  • 北京西站附近的景点有哪些推广信息发布平台
  • web网站开发 网页模板智能建站网站模板
  • 品牌网站设计地址搜索引擎优化的含义
  • 淘宝网站建设需要哪些技术互联网营销师含金量
  • 百度竞价排名魏则西seo竞价
  • wordpress站点语言嘉兴新站seo外包
  • 优化网站的步骤案列制作自己的网页
  • 在百度怎么做网站和推广博客推广的方法与技巧
  • wordpress获取首页url班级优化大师
  • 做网站在2021谷歌搜索入口
  • 诚信建设万里行网站小程序开发公司
  • 横琴建设局网站嘉兴seo优化
  • 淘宝客网站WordPress微信营销的成功案例
  • 永久网站推广seo外包公司如何优化
  • 学校网站的平台用途及建设规划百度指数功能模块有哪些
  • 重庆是哪个省份杭州seo网站优化公司
  • 做外贸在哪个网站注册seo诊断方案
  • 中文网站css font-family百度竞价推广什么意思
  • 厦门网站建设方案服务老铁外链工具
  • 专业网站设计开发网站高端网站优化公司
  • 做面料那几个网站公司产品推广文案
  • 网站开发公司北京深圳做网站的
  • 外贸公司组织架构图seo外链优化方法
  • 图书馆门户网站建设会议记录对网站提出的优化建议
  • 太原免费自助建站模板互动营销案例都有哪些